Question

Total surface area of a cube is 5400 sq. cm. Find the surface area of all vertical faces of the cube.

Answer 1

Given: Total surface area of cube = 5400 sq.cm. 

To find: Surface area of all vertical faces of the cube 

Solution:

i. Total surface area of cube = 6l² 

∴ 5400 = 6l² 

∴ \(\frac{5400}6\) =  l² 

∴ l² = 900 

ii. Area of vertical faces of cube = 4l² 

= 4 x 900 = 3600 sq.cm. 

∴ The surface area of all vertical faces of the cube is 3600 sq.cm.