Question

The centripetal acceleration of a satellite that circles the earth at an altitude 400 km above see level is (g on the surface of earth is `10m//s^(2)`, Radius of the earth is `6.4xx10^(6)m`)
A. `8.75m//s^(2)`
B. `9.2m//s^(2)`
C. `10m//s^(2)`
D. `7.5m//s^(2)`

Answer 1

Correct Answer - a
`g_(2)=g[1-(2h)/(R)]=10[1-(2xx400)/(6400)]`
`=10[1-(1)/(8)]`
`=10[(8-1)/(8)]=(70)/(8)=8.75m//s^(2).`