Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
158 views
in Physics by (86.7k points)
closed by
An automobile egine develops `60 pi` kilowatt of power when it is rotating at the speed of 1800 rev/min, then the torque it can transfer to the wheels is
A. 100 Nm
B. 10 Nm
C. 1000 Nm
D. 1800 Nm

1 Answer

0 votes
by (84.9k points)
selected by
 
Best answer
Correct Answer - C
`P = tau omega " " therefore tau =(60 pi xx 10^(3))/(2pi xx 30)=1000 Nm`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...