Question

The displacement of a SHO is given by,
`y=0.4sin(10pit+pi//3)cos(10pit+pi//3)`
The ratio of maximum velocity to the maximum acceleration of the particle is
A. `10 pi s`
B. `(1)/(10pi)s`
C. `20 pi s`
D. `(1)/(20pi)s`

Answer 1

Correct Answer - D
`y=0.2sin2(10pit+(pi)/(3))`
`=0.2sin(20pit+(2pi)/(3))`
`(V_("max"))/(a_("max"))=(Aomega)/(Aomega^(2))=(1)/(omega)=(1)/(20pi)s`.