Question

At 783 K in the reaction `H_(2)(g)+I_(2)(g) hArr 2HI(g)`, the molar concentrations `("mol"^(-1))"of "H_(2),I_(2)and HI` at some instant of time are `0.1, 0.2 and 0.4`, respectively. If the equilibrium constant is 46 at the same temperature, then as the reaction proceeds
A. the amount of HI will increase
B. the amount of HI will decrease
C. the amount of `H_(2) and I_(2)` will increase
D. the amount of `H_(2) and I_(2)` will not change

Answer 1

Correct Answer - A
Reaction quotient
`Q=([HI]^(2))/([H_(2)][I_(2)])=(0.4xx0.4)/(0.1xx0.2)`
`Q=8`
`Q ltK`
So reaction will proceeds in forward direction. ltbr? Hence amount of HI increases.