Question

A simple pendulum with a bob of mass ‘m’ oscillates from A to C and back to A such that PB is H . If the acceleration due to gravity is ‘g’ then the velocity of the bob as it passes through B is
A. zero
B. 2gh
C. mgh
D. `sqrt(2gh)`

Answer 1

Correct Answer - D
By the law of conservation of energy
P.B. at A = K.E. at B.
`mgh_(A)=(1)/(2)mv_(B)^(2)`
`V_(B)=sqrt(2gh)`