Question

A rubber cube of side 10 cm has one side fixed to a horizontal surface. A tangential force of 2000 N is applied on the opposite face. The distance through which the strained side moves will be (Rigidity modulus of the material is `200xx10^(4)N//m^(2), g=10m//s^(2)`)
A. 1 cm
B. 10 cm
C. 1.4 cm
D. 20 cm

Answer 1

Correct Answer - A
`eta=(Fh)/(A x) " " therefore x=(Fh)/(A eta)`
`therefore x=(2000 xx 0.1)/(0.1xx0.1xx2xx10^(6))=1xx10^(-2)m`
`=1 cm`