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A rope 1 cm in diameter breaks, if the tension in it exceeds 500 N. The maximum tension that may be given to similar rope of diameter 3 cm is
A. 2000 N
B. 1000 N
C. 500 N
D. 250 N

1 Answer

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Correct Answer - A
`(F_(2))/(F_(1))=((r_(2))/(r_(1)))^(2)=(4)/(1)`
`F_(2)=4F_(1)=4xx500=2000N`.

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