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The length of a given open end and closed end pipes are `l_0 " and " l_c` respectively. If both the pipes emit same fundamental notes, then the ratio `l_0//l_c` is
A. `sqrt2:1`
B. `2:1`
C. `1:2`
D. `1:sqrt2`

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Correct Answer - B
`n_0 = (v)/(2l_0) " and " n_c = (v)/(4l_c)`
`n_0/n_c = (v)/(2l_0) xx(4l_c)/(v) = (2l_c)/(l_0) therefore l_0/l_c = 2/1`

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