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In a biprism experiement, by using light of wavelength `5000Å`, `5mm` wide fringes are obtained on a screen `1.0m` away from the coherent sources. The separation between the two coherent sources is
A. 1 mm
B. `0.1 mm`
C. `0.05 mm`
D. `0.01 mm`

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Best answer
Correct Answer - B
`d=(D)/(beta) lambda=(1xx5xx10^(-7))/(5xx10^(-3))=0.1 mm`

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