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Due to 10 A of current flowing in a circular coil of 10 cm radius , the magnetic field produced at its centre is `3.14xx10^-3` Wb/`m^2`. The number of turns in the coil will be
A. 5000
B. 100
C. 50
D. 25

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Correct Answer - C
`B=(mu_0nI)/(2A)`
`because n=(3.14xx10^-3xx2xx10^-1)/(4xxpixx10^-7xx10)=50`

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