Fewpal
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(i) 4Na(s) + O2(g) → 2Na2O(s) 

(ii) CuO(s) + H2(g) → Cu(s) + H2O(l)

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(i). Sodium (Na) is oxidised as it gains oxygen and oxygen gets reduced. 

(ii). Copper oxide (CuO) is reduced to copper (Cu) while hydrogen (H2) gets oxidised to water (H2O).

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