Question

In a reverse biased diode, when the applied voltage changes by `1V`, the current is found to change by `0.5muA`. The reversebiase resistance of the diode is
A. `2xx10^5 Omega`
B. `2xx10^6 Omega`
C. `200 Omega`
D. `2 Omega`

Answer 1

Correct Answer - B
`R=(DeltaV)/(DeltaI)=1/(0.5xx1^(-6)) = 10^6/(1//2)=2xx10^6 Omega`