Question

A tansmitting antenna at the top of a tower has a height 32 m and that of the receiving antenna is 50 m. What is the maximum distance between them for satisfactory communication in line of sight mode ? Given radius of earth is `6.4 xx 10^(6) m`.
A. 45.5 km
B. 40.5 km
C. 35 km
D. 32 km

Answer 1

Correct Answer - A
`h_T`=32 m , `h_"Receiver"`=100 m
`d_"max"=sqrt(2Rh_T) + sqrt(2Rh_"Receiver")`
`=sqrt(2xx64xx10^5xx32)+sqrt(2xx64xx10^5xx50)`
`=64xx10^2xxsqrt10+8xx10^3xxsqrt10`
`=144xx10^2 sqrt10`
=`45.5 xx 10^3` = 45.5 Km