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KBr is 80 % dissociated in solution. The freezing point of a 0.5 molal solution is `(K_(f) "water" = 1.86^(@)C/m)`
A. 273 K
B. 277 K
C. 271.326 K
D. 269 K

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Correct Answer - C
For KBr,`i = 1 + alpha = 1 + 0.80 = 1.80`
`Delta T_(f) = i K_(f) m = 1.80 xx 1.86 xx 0.5 = 1.674^(@)`
`T_(f) = 273 - 1.674 = 271.326 K.`

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