Question

`9.65` amp of current was passed for one hour through Daniel cell. The loss of mass of zinc anode is
A. 11.77 g , 11.43 g
B. 11.43 g , 11.77 g
C. 23.54 g , 22.84 g
D. 22.86 g 23.54 g

Answer 1

Correct Answer - A
`Q = 9.65 xx 60 xx 60 = 34740` C
At anode ` : Zn to Zn^(2+) + 2e^(-)`
Loss mass of Zn by `2 xx 96500 C = 65.4` g
`therefore ` Loss in mass by 34740 C = 11.77 g
At cathode `: Cu^(2+) + 2e^(-) to Cu` .
Gain in mass of Cu by `2 xx 96500 C = 63.5`g
`therefore` Gain in mass of Cu by 34740 C
= `(63.5)/(2 xx 96500) xx 3474 = 11 .43`g