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The electrochemical equivalent of silver is `0.001114` g . When an electric current of 0.5 ampere is passed through an aqueous silver nitrate solution for 200 seconds , the amount of silver deposited is
A. 1.118 g
B. `0.1118 g`
C. `5.590` g
D. `0.5590 g`

1 Answer

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Best answer
Correct Answer - B
`W = Z xx C xx t = 0.00118 xx 0.5 xx 200 = 0.1118` g

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