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The charge required for the reduction of 1 mole of `Cr_(2)O_(7)^(2-)` ions to `Cr^(3+)` is
A. 96500 C
B. `2 xx 96500 C `
C. `3 xx 96500 C`
D. `6 xx 96500 C`.

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Correct Answer - D
`Cr_(2)O_(7)^(2-) to 2 Cr^(3+)` i.e.
`2 Cr^(6+) + 6e^(-) to 2 Cr^(3+)` .
Thus 1 mole of `Cr_(2)O_(7)^(2-)` ions require 6 F

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