Question

An ideal inductor is in turn put across 220 V, 50 Hz and 220 V, 100 Hz supplies. The current flowing through it in the two cases will be
A. equal
B. different
C. zero
D. infinite

Answer 1

Correct Answer - B
The current in the inductor coil is given by
`I = (V)/(X_(L))=(V)/(2pi upsilon L)`
Since frequency `upsilon`in the two cases is different, hence the current in two cases will be different.