Correct Answer - C
Here, `I_(t)=1.8A A: mu_(1)=(80)/(100)=0.80: mu_(2)=0.6`
`I_(t)=I_(c)sqrt(1+mu_(1)^(2)//2)`
`I_(c)=(1)/(sqrt(1+mu_(1)^(2)//2))=(1.8)/(sqrt(1+(0.8)^(2)//2))=(1.8)/(sqrt(1.32))`
`I_("net total")=I_(c)sqrt(1+(mu_(1)^(2))/(2)+(mu_(2)^(2))/(2))`
`=(1.8)/sqrt(1.32)sqrt(1+((0.8)^(2))/(2)+((0.6)^(2))/(2))=1.91A`