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बिंदु A से B तक `10^(9)` इलेक्ट्रॉन `10^(-3)`सेकंड में प्रवाहित हो रहे हैं | विधुत धारा की गणना कीजिये एवं इसकी दिशा बताइये |

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दिया हैं : इलेक्ट्रॉनों की संख्या `n=10^(9)`
`:. " "`कुल आवेश q=ne
`=10^(9)xx1.6xx10^(-19)=1.6xx10^(-10)`कूलॉम
समय `t=10^(-3)`सेकंड
`:. " "` विधुत धारा `I=(q)/(t)`
`=(1.6xx10^(-10))/(10^(-3))=1.6xx10^(-7)`ऐम्पियर
विधुत धारा की दिशा B से A की ओर होगी |

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