Question

0.15g of a substance dissolved in 15g of a solvent boiled at a temp. higher by `0.216^(@)C` than that of the pure solvent. Find out the molecular weight of the substance `(K_(b)` for solvent is `2.16^(@)C`)
A. 1.01
B. 10.1
C. 100
D. 10

Answer 1

Correct Answer - C
`M = (K_(b).W_(b).1000)/(DeltaT_(b).W_(A))`
`=(2.16 xx 0.15 xx 1000)/(216 xx 15) = 100`