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Equivalent resistance (in ohm) of the given network is

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Equivalent resistance (in ohm) of the given network is
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A. 28
B. 18
C. 26
D. 25
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Correct Answer - B
Between points A and B all resistance are combined in series
`therefore R_("eq")=3Omega+4Omega+5Omega+6Omega=18Omega`
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