Correct option is (D) 12 m
Since, the ratio of areas of two similar triangles is square of the ratio of their corresponding sides/Altitudes/Medians.
\(\therefore\) \(\frac{\text{Area of bigger triangle}}{\text{Area of smaller triangle}}=(\frac{\text{Median of bigger triangle}}{\text{Median of smaller triangle}})^2\)
\(\therefore\) \((\frac{\text{Median of bigger triangle}}{10})^2=\frac{36}{25}\)
\(\Rightarrow\) \(\frac{\text{Median of bigger triangle}}{10}=\sqrt{\frac{36}{25}}=\frac65\)
\(\therefore\) Median of bigger triangle \(=\frac65\times10\)
\(=6\times2=12\,m\)