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Iodine is liberated from sodium iodate by reacting with
A. dil. `H_2SO_4`
B. `KMnO_4`
C. `NaHSO_3`
D. HCl

1 Answer

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Best answer
Correct Answer - C
This can be done with conc. `H_2SO_4 or NaHSO_3`
`2 NaIO_3 + 5 NaHSO_3 to 3NaHSO_4 + 2 Na_2SO_4+I_2+ H_2O`

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