Correct option is: A) \(\frac 32\)
tan \(36^\circ\) tan \(54^\circ\) + sin \(30^\circ\)
= tan (\(90^\circ\) - \(54^\circ\) ) tan \(54^\circ\) + \(\frac 12\) (\(\because\) sin \(30^\circ\) = \(\frac 12\))
= cot \(54^\circ\) tan \(54^\circ\) + \(\frac 12\) ( \(\because\) tan (\(90^\circ\) -\(\theta\) ) = cot \(\theta\))
= \(\frac 1{tan \, 54^\circ} \times\) tan \(54^\circ\) + \(\frac 12\) (\(\because\) cot \(\theta\) = \(\frac 1{tan\,\theta}\))
= 1 + \(\frac 12\) = \(\frac 32\)