Correct option is (B) 5
Let \(\alpha\;and\;\frac1\alpha\) are zeros of given polynomial f(x).
\(\therefore\) Product of zeros \(=\frac{\text{constant term}}{\text{coefficient of }x^2}=\frac k5\)
\(\Rightarrow\) \(\alpha.\frac1\alpha\) \(=\frac k5\)
\(\Rightarrow\) \(\frac k5=1\)
\(\Rightarrow\) k = 5