Correct option is (A) x + 1
x = 1 & x = -3 are zeros of polynomial \(x^3 + 3x^2 – x – 3 .\)
Let the other zero be x.
\(\therefore\) Sum of zeros \(=\frac{\text{-coefficient of }x^2}{\text{coefficient of }x^3}\) \(=\frac{-3}1\) = -3
\(\therefore\) 1 + (-3) + \(\alpha\) = -3
\(\Rightarrow\) \(\alpha\) = -1
\(\therefore\) x = -1 is another zero of polynomial \(x^3 + 3x^2 – x – 3 .\)
\(\Rightarrow\) (x+1) is a other factor of polynomial \((x^3+3x^2-x-3).\)
