Correct option is (D) \(\frac{-x^4 + 31x^2 +20}{x^4 -16}\)
\(\frac{x+2}{x-2}+\frac{x-2}{x+2}-\frac{3(x^2-1)}{x^2+4}\)
\(=\frac{(x+2)^2+(x-2)^2}{(x-2)(x+2)}-\frac{3(x^2-1)}{x^2+4}\)
\(=\frac{2(x^2+4)}{x^2-4}-\frac{3(x^2-1)}{x^2+4}\)
\(=\frac{2(x^2+4)^2-3(x^2-1)(x^2-4)}{(x^2-4)(x^2+4)}\)
\(=\frac{2(x^4+8x^2+16)-3(x^4-5x^2+4)}{x^4-16}\)
\(=\frac{-x^4 + 31x^2 +20}{x^4 -16}\)