Correct option is: A)\(\frac 16\)
There are 3 greeting cards and their 3 covers
Since, first greeting card has 3 possibilities to covering in which only one cover is a perfect cover for first greeting card.
For second greeting card 2 possibilities covers left in which only one cover is a perfect cover for second greeting card.
For third greeting card only one cover (Possibility) left.
\(\therefore\) Total No of possible outcomes = 3 \(\times\) 2 \(\times\) 1 = 6 in which only one outcome has 3 greeting card covered by their correct (Corresponding) cover.
\(\therefore\) Total No of favourable outcomes = 1
The probability of correctly matching of all greeting cards and covers is
P = \(\frac {Total \,No\, of \,favourable \,outcomes}{Total \,No \, of \,Possible \, outcomes}\)= \(\frac 16\)