Question

For a cell reaction involving a two-electron change, the standard e.m.f. of the cell is found to be `0.295V` at `25^(@)C`. The equilibrium constant of the reaction at `25^(@)C` will be:
A. `29.5xx10^(-2)`
B. 10
C. `1xx10^(10)`
D. `1xx10^(-10)`

Answer 1

Correct Answer - C
(c ) `"log "K=(nxxE_(cell)^(@))/(0.059)=(2xx0.295)/(0.059)=10`
`K="Antilog " 10=1xx10^(10)`.