Correct option is (A) 36
Let the number be ab or (10a+b).
Given that ratio of two-digit number and the sum of digit of that number is 4 : 1.
\(\therefore\) \(\frac{10a+b}{a+b}=\frac41\)
\(\Rightarrow\) 10a+b = 4a+4b
\(\Rightarrow\) 6a = 3b
\(\Rightarrow\) b = 2a _____________(1)
According to \(2^{nd}\) condition, we have
b = a+3 _____________(2)
\(\Rightarrow\) 2a = a+3 (From (1))
\(\Rightarrow\) a = 3
\(\therefore b=2\times3=6\) (From (1))
Hence, the required number is ab = 36.
