Correct option is (A) \(4\sqrt{15}\)
Given that roots of the equation \(12x^2+mx+5=0\) are real and equal.
\(\therefore m^2-4\times12\times5=0\)
\(\Rightarrow m^2=240\)
\(\Rightarrow m^2=16\times15\)
\(\Rightarrow m=\pm\sqrt{16\times15}\)
\(=\pm4\sqrt{15}\)