Correct option is (A) no roots
Given equation is \(x-\frac{7}{x-3}=3-\frac{7}{x-3}\)
\(\Rightarrow\) \(x=3-\frac{7}{x-3}+\frac{7}{x-3}\)
\(\Rightarrow\) x = 3
But \(x\neq3\) as \(\frac{7}{x-3}\) is a rational term present in given equation.
\(\therefore\) Given equation has no roots.