Question

The binding energies per nucleon for deuteron (`._1H^2`) and helium (`._2He^4)` are `1.1 MeV` and `7.0 MeV` respectively. The energy released when two deutrons fuse to form a helium nucleus (`._2He^4`) is……..
A. `13.9 MeV`
B. `26.9 MeV`
C. `23.6 MeV`
D. `19.2 MeV`

Answer 1

Correct Answer - C
Given that `.^(2)H_(1) + .^(2)H_(1) rarr .^(4)He_(2) +` energy total B.E. of deuterium nucleus `= 28 MeV` On conservating energy on both sides we get `("Energy")_("Deutron") xx 2 = ("Energy")_(He) +` Energy released
`rArr 4.4 = 28 + E`
`rArr E = 28 - 4.4 = 23.6 MeV`