Question

The peak value of an alternating emf E given by
E = `underset(o)(E) ` cos `omega`t
is 10 V and frequency is 50 Hz . At time t = (1/600) s, the instantaneous value of emf is
A. 10 V
B. 5`sqrt 3` V
C. 5 V
D. 1 V

Answer 1

Correct Answer - B
E = 10 cos(`2pi`ft) = 10 cos (`2pi xx 50 xx 1/600`)
= 10 cos`pi`/6 = `5sqrt 3`V