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Calculate the amount of ice that will separate out on cooling containing `50 g `of ethylene glycol in `200 g` of water to `-9.3^(@)C (K_(f)` for water =`1.86 K mol^(-1) kg`)

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Calculation of the amount of water present in the antifreeze solution.
Mass of ethylene glycol`(W_(B))=50 g`
Molar mass of ethylene glycol `(M_(B))= (62 g mol^(-1))`
Depression in freezing point`(DeltaT_(f))=0-(-9.3^(@)C)=9.3^(@)C=9.3 K`
Molal depressio constant `(K_(f))=1.86 K kg mol^(-1)`
Mass of water `(W_(A))=(W_(B)xxK_(f))/(M_(B)xxDeltaT_(f))=((50g)xx(1.86 K mol^(-1)))/((62g mol^(-1))xx(9.3 K))`
Calculation of the amount of ice separetino on colling
The water which is not a part of antifreeze solution will separate as ice onm cooling. It mat be calculated as

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