# Calculate the amount of ice that will separate out on cooling containing 50 g of ethylene glycol in 200 g of water to -9.3^(@)C (K_(f) for water

35 views

closed
Calculate the amount of ice that will separate out on cooling containing 50 g of ethylene glycol in 200 g of water to -9.3^(@)C (K_(f) for water =1.86 K mol^(-1) kg)

by (90.8k points)
selected

Calculation of the amount of water present in the antifreeze solution.
Mass of ethylene glycol(W_(B))=50 g
Molar mass of ethylene glycol (M_(B))= (62 g mol^(-1))
Depression in freezing point(DeltaT_(f))=0-(-9.3^(@)C)=9.3^(@)C=9.3 K
Molal depressio constant (K_(f))=1.86 K kg mol^(-1)
Mass of water (W_(A))=(W_(B)xxK_(f))/(M_(B)xxDeltaT_(f))=((50g)xx(1.86 K mol^(-1)))/((62g mol^(-1))xx(9.3 K))
Calculation of the amount of ice separetino on colling
The water which is not a part of antifreeze solution will separate as ice onm cooling. It mat be calculated as