Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
277 views
in Physics by (91.5k points)
closed by
The focal length of objective and eye lens of a microscope are `4 cm` and `8 cm` respectively. If the least distance of distinct vision is `24 cm` and object distance is `4.5 cm` from the objective lens, then the magnifying power of the microscope will be
A. 18
B. 32
C. 64
D. 20

1 Answer

0 votes
by (91.6k points)
selected by
 
Best answer
Correct Answer - B
(b) For objective lens,
`1/(f_(o))=1/v_(o)-1/u_(o)`
or `1/4=1/v_(o)-1/((-4.5))rArrabs(v_(o))=36 cm`
`therefore` Magnifying power, `abs(M)=u_(0)/v_(0)(1+D/(f_(e)))=36/4.5(1+24/8)=32`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...