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Equimolar aqueous solutions of NaCI and `BACI_(2)` are prepared. If the freezing point of NaCI is `-2^(@)C`, the freezing point of `BaCI_(2)` solution is expected to be:
A. `-2^(@)C`
B. `-3^(@)C`
C. `-1.5^(@)C`
D. `-1.66^(@)C`

1 Answer

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Best answer
Correct Answer - b
`DeltaT_(f)("Colligative property")` in linked with number of particles or ions in solution
`NaCItoNa_((aq))^(+)+CI_((aq))^(-)`
` BaCI_(2)toBa_((aq))^(2+)+2CI_((aq))^(-)`
`"If "alph a"for " NaCI is -2^(@)C`
`"Then " alpha "for" BaCI_(2) "is expected to be" =-3^(@)C.`

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