Question

The density (in g `mL^(-1)`) of 3.60 M sulphuric acid solution this is 29% `H_(2)SO_(4)` (molar mass =98 g `mol^(-1)`) by mass will be :
A. 1.45
B. 1.64
C. 1.88
D. 1.22

Answer 1

Correct Answer - d
By definition, `3.6 M (3xx98=352.8 g) of H_(2)SO_(4)` are present in 1000 mL of solution.
29.0 g of acid are present in solution=100 g
325.8 of acid are present in soluion
`((100g))/((29.0 g))xx(352.8 g)`
=1216 g
`"Density of solution"=("Mass of solution")/("Volume of solution")`
`((1216g))/((1000mL))=`1.22 g `mol^(-1)`