Question

`MX_(2)` dissociates into `M^(2+)" and " X^(-)` ions in aqueous solution with degree of dissociation `(alpha)` of 0.5. What is the ratio of the observed depression in freezing point of the aqueous solution to the voluem of the depression in freezing point in the absene of the ionic dissociation ?

Answer 1

`Mx_(2)overset((aq))hArrM^(2+)(aq)+2X^(-)(aq)`
`"Degree of dissociation"(alpha)=(i-1)/(n-1)`
`0.5=(i-1)/(3-1)=(i-1)/2or i=0.5xx2+1=2`
I gives the ratio of observed depression in freezing point to the normal depression in freezing point value
The ratio is 2