Question

Based on the following information, determine value `x` and `y` :
`underset(0.643 g)((CH_(3))_(x)AlCl_(y))rarrxunderset(0.222g)(CH(g)+yCl^(-)+Al^(3+)overset(AgNO_(3))rarrunderset(0.996g)(AgCl(S)`

Answer 1

Correct Answer - x=2,y=1
If M is molar mass of `(CH_3)_xAlCl_y`
`m(CH_4)=(0.643 x)/Mxx16=0.22`
and `m(AgCl)=(0.643 y)/Mxx143.5=0.996`
dividing : `x/y=2`, Also `M=15x+27+35.5y=15x+27+(35.5x)/2=32.75x+27`
`implies (0.643x xx16)/(32.75x +27)=0.222 implies x=1.98~~2 implies y=1`