(a). 0.4 mole of nitrogen (N)
Number of atoms of N = Number of moles × Avogadro’s constant
= 0.4 mol × 6.022 × 1023 atoms/mol
= 2.4088 × 1023 atoms of N
(b). 1.6 g of Sulphur (S)
Molar mass of sulphur = 32 g mol-1
Number of moles = \(\frac{Mass\,of\,a\,substance}{Molar\,mass\,of\,a\,substance}\)
= \(\frac{1.6\,g}{32\,g\,mol^{-1}}\)
= 0.05 mol
Number of atoms of S = Number of moles × Avogadro’s constant
= 0.05 mol × 6.022 × 1023 atoms/mol
= 0.3011 × 1023 atoms
= 3.011 × 1022 atoms of S
∴ (a) Number of nitrogen atoms in 0.4 mole = 2.4088 × 1023 atoms of N
(b) Number of sulphur atoms in 1.6 g = 3.011 × 1022 atoms of S