Question

For a binary liquid solution of A and B. `P_A^0`=pure vapour pressure of A . `P_B^0`=pure vapour pressure of B. `X_A`=mole fraction of A in liquid phase.`Y_A`=mole fraction of A in vapour phase.
`{:("Column I","Column II"),((A)P_A^0gtP_B^0"[Ideal liquid solution]",(p)X_A=Y_A),((B)"Azeotropic mixture",(q)X_AltY_A),(( C)"Equimolar ideal mixture of A & B with "P_A^0ltP_B^0,(r)X_BltY_B),((D)"Equimolar ideal mixture of A & B with "P_A^0=P_B^0,(s)Y_BgtY_A),(,(t)X_B=Y_B):}`

Answer 1

Correct Answer - A-q ; B-p,t ; C-r,s ; D-p
(A)`P_A^0gt P_B^0` means A is more volatile than B and therefore A will be richer in vapour phase , [or `Y_A=X_A(P_A^0)/P_T`]
(B)For azeotropes composition of vapour phase and liquid phase is same
(C )For `P_A^0 lt P_B^@ ,X_B lt Y_B and Y_B gt Y_A` for an equimolar ratio.
(D) For `P_A^0=P_B^0,X_A=Y_A` for an equimolar ratio.