Question

The `E_(Call)^(@)=1.18V` for `Zn(s)||Zn^(+2)(1M)||Cu^(+2)(1M)|Cu(s)`. The value of `x` if when excess granulated zinc is added to `1M Cu^(+2)` solution the `[Cu^(+2)]_(eq)` becomes `10^(-x)M` is `(T=298 K ,(2.303RT)/(F)=0.059)`

Answer 1

Correct Answer - 40
`E_("cell")=E_("cell")^@ - 0.0590/2 "log" ([Zn^(+2)])/([Cu^(+2)])`
At equilibrium `E_("cell")=0`
`0.0590/2 "log" 1/10^(-x)=1.18`