Question

A block of mass m is placed on a smooth wedge of inclination `theta`. The whole system is accelerated horizontally, so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be
A. `mg sin theta`
B. `mg`
C. `mg//cos theta`
D. `mg cos theta`

Answer 1

Correct Answer - C

`therefore mg sin theta=ma cos theta`
`N=mg cos theta+ ma sin theta`
`theta N=mg cos theta+ m sin thetaxxgxx(sintheta)/(cos theta)`
`N=(mg)/(cos theta)`