Question

A gaseous hydrocarbon has 85% carbon and vapour density of 28. The possible formula of the hydrocarbon will be
A. `C_(6) H_(3)`
B. `C_(2)H_(8)`
C. `C_(2)H_(2)`
D. `C_(4)H_(8)`

Answer 1

Correct Answer - D

Empirical formula is `CH_(2)`
Mol. Mass `=2xxVD=2xx28=56`
`n=("Mol. Formula mass ")/("Emp . Formula mass")=(56)/(14)=4`
Hence mol. Formula `=(CH_(2))_(n)=(CH_(2))_(4)=C_(4)H_(8)`