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Empirical formula of a compound is `CH_(2)O` and its molecular mass is 90. The molecular formula of the compound is

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Empirical formula of a compound is `CH_(2)O` and its molecular mass is 90. The molecular formula of the compound is
A. `C_(3)H_(6)O_(3)`
B. `C_2H_4O_2`
C. `C_6H_(12)O_(6)`
D. `CH_2O`
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Correct Answer - A
E.F weight `=1.2+1xx2+16=30`
Molecular mass=90
`therefore n=("Molecular mass")/("E.F. mass")=90/30=3`
Hence M.F `=3xxCH_(2)O=C_(3)H_(6)O_(3)`
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