Question

Steam at `100^(@)C` is passed into `1.1 kg` of water contained in a calorimeter of water equivalent `0.02kg` at `15^(@)C` till the temperature of the calorimeter and its content rises to `80^(@)C`. What is the mass of steam condensed? Latent heat of steam = `536 cal//g`.

Answer 1

Heat required by (calorimeter +water)
`Q = (m_(1)c_(1) +m_(2)c_(2))Deltatheta = (0.02+1.1xx1)(80-15) = 72.8kcal`
If m is mass of steam condensed , then heat given by steam
`Q` =m`L` +mc `Deltatheta` = `m xx536 + m xx1xx(100-80)=556m` ` therefore 556m = 72.8`
`therefore` Mass of steam condensed `m=72.8/556 = 0.130kg`