Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
131 views
in Physics by (91.6k points)
closed by
A gas is enclosed in a cylinder with a movable frictionless piston. Its initial thermodynamic state at pressure `P_i=10^5` Pa and volume `V_i=10^-3m^3` changes to a final state at `P_f=(1//32)xx10^5Pa and V_f=8xx10^-3m^3` in an adiabatic quasi-static process, such that `P^3V^3=constant.` Consider another thermodynamic process that brings the system form the same initial state to the same final state in two steps: an isobaric expansion at `P_i` followed by an isochoric (isovolumetric ) process at volume `V_r.` The amount of heat supplied to the system i the two-step process is approximately
A. `112J`
B. `294J`
C. `588J`
D. `813J`

1 Answer

0 votes
by (91.5k points)
selected by
 
Best answer
Correct Answer - C
In adiabatic process `P^(3)V^(5)` = constant
`implies PV^(5//3)` = constant
`implies gamma=(5)/(3) implies C_(V) = (3)/(2)R "and" C_(P) = (5)/(2)R`
In another process
image
`DeltaQ = nC_(P)DeltaT + nC_(V)DeltaT = (5)/(2)nR (T_(B) - T_(A)) + (3)/(2)nR(T_(C)- T_(B))`
`DeltaQ = (5)/(2)(P_(B)V_(B) - P_(A)V_(A))+ (3)/(2)(P_(C)V_(C) - P_(B)V_(B))`
Putting value
`DeltaQ = 587.5J approx 588J`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...